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Update pointer examples and comments
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@ -194,26 +194,41 @@ printf("%d\n", (short) 65537); // => 1 (Max short = 65535)
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// Pointers
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///////////////////////////////////////
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// You can retrieve the memory address of your variables,
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// then mess with them.
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// A pointer is a variable declared to store a memory address. Its declaration will
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// also tell you the type of data it points to. You can retrieve the memory address
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// of your variables, then mess with them.
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int x = 0;
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printf("%p\n", &x); // Use & to retrieve the address of a variable
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// (%p formats a pointer)
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// => Prints some address in memory;
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// Pointer types end with * in their declaration
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int* px; // px is a pointer to an int
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px = &x; // Stores the address of x in px
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printf("%p\n", px); // => Prints some address in memory
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// To retreive the value at the address a pointer is pointing to,
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// put * in front to de-reference it.
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printf("%d\n", *px); // => Prints 0, the value of x, which is what px is pointing to the address of
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// You can also change the value the pointer is pointing to.
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// We'll have to wrap the de-reference in parenthesis because
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// ++ has a higher precedence than *.
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(*px)++; // Increment the value px is pointing to by 1
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printf("%d\n", *px); // => Prints 1
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printf("%d\n", x); // => Prints 1
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int x_array[20]; // Arrays are a good way to allocate a contiguous block of memory
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int xx;
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for(xx=0; xx<20; xx++){
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x_array[xx] = 20 - xx;
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} // Initialize x_array to 20, 19, 18,... 2, 1
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// Pointer types end with *
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int* x_ptr = x_array;
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// This works because arrays are pointers to their first element.
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// This works because an array name is bound to the address of its first element
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// Put a * in front to de-reference a pointer and retrieve the value,
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// of the same type as the pointer, that the pointer is pointing at.
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// Arrays are pointers to their first element
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printf("%d\n", *(x_ptr)); // => Prints 20
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printf("%d\n", x_array[0]); // => Prints 20
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