Fixing last remaining carriage return formatting

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Andrew Ryan Davis 2020-08-06 14:50:39 -07:00 committed by GitHub
parent b70f50c666
commit af19db1735
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@ -21,7 +21,8 @@ like so
\
*/
// Note: Using C# multi-line around Q# because there doesn't appear to be a markdown formatter yet.
// Note: Using C# multi-line around Q#
// there doesn't appear to be a Q# markdown formatter yet.
/////////////////////////////////////
// 1. Quantum data types and operators
@ -40,7 +41,8 @@ using (qs = Qubit[2]) {
// If you want to change the state of a qubit
// you have to do this by applying quantum gates to the qubit.
H(q[0]); // This changes the state of the first qubit
// from |0⟩ (the initial state of allocated qubits) to (|0⟩ + |1⟩) / sqrt(2).
// from |0⟩ (the initial state of allocated qubits)
// to (|0⟩ + |1⟩) / sqrt(2).
// q[1] = |1⟩; - this does NOT work, you have to manipulate a qubit by using gates.
// You can apply multi-qubit gates to several qubits.
@ -48,7 +50,8 @@ using (qs = Qubit[2]) {
// You can also apply a controlled version of a gate:
// a gate that is applied if all control qubits are in |1⟩ state.
// The first argument is an array of control qubits, the second argument is the target qubit.
// The first argument is an array of control qubits,
// the second argument is the target qubit.
Controlled Y([qs[0]], qs[1]);
// If you want to apply an anti-controlled gate
@ -74,7 +77,8 @@ let d = 1.0; // This defines a Double variable d equal to 1
// Arithmetic is done as expected, as long as the types are the same
let n = 2 * 10; // = 20
// Q# does not have implicit type cast,
// so to perform arithmetic on values of different types, you need to cast type explicitly
// so to perform arithmetic on values of different types,
// you need to cast type explicitly
let nd = IntAsDouble(2) * 1.0; // = 20.0
// Boolean type is called Bool
@ -190,9 +194,9 @@ operation QRNGDemo() : Unit {
mutable bits = new Int[5]; // Array we'll use to store bits
using (q = Qubit()) { // Allocate a qubit
for (i in 0 .. 4) { // Generate each bit independently
H(q); // Apply Hadamard gate prepares equal superposition
let result = M(q); // Measure the qubit to get 0 or 1 with 50/50 prob
let bit = result == Zero ? 0 | 1; // Convert measurement result to an integer
H(q); // Hadamard gate sets equal superposition
let result = M(q); // Measure qubit gets 0|1 with 50/50 prob
let bit = result == Zero ? 0 | 1; // Convert measurement result to integer
set bits w/= i <- bit; // Write generated bit to an array
}
}