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markdown syntax issue
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@ -139,6 +139,7 @@ Take the church number 2 for example:
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`2 = λf.λx.f(f x)`
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`2 = λf.λx.f(f x)`
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For the inner part `λx.f(f x)`:
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For the inner part `λx.f(f x)`:
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```
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```
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λx.f(f x)
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λx.f(f x)
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= S (λx.f) (λx.(f x)) (case 3)
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= S (λx.f) (λx.(f x)) (case 3)
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@ -147,6 +148,7 @@ For the inner part `λx.f(f x)`:
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```
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```
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So:
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So:
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```
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```
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2
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2
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= λf.λx.f(f x)
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= λf.λx.f(f x)
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@ -156,6 +158,7 @@ So:
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```
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```
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For the first argument `λf.(S (K f))`:
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For the first argument `λf.(S (K f))`:
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```
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```
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λf.(S (K f))
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λf.(S (K f))
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= S (λf.S) (λf.(K f)) (case 3)
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= S (λf.S) (λf.(K f)) (case 3)
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@ -164,6 +167,7 @@ For the first argument `λf.(S (K f))`:
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```
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```
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For the second argument `λf.(S (K f) I)`:
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For the second argument `λf.(S (K f) I)`:
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```
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```
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λf.(S (K f) I)
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λf.(S (K f) I)
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= λf.((S (K f)) I)
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= λf.((S (K f)) I)
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@ -174,6 +178,7 @@ For the second argument `λf.(S (K f) I)`:
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```
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```
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Merging them up:
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Merging them up:
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```
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```
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2
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2
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= S (λf.(S (K f))) (λf.(S (K f) I))
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= S (λf.(S (K f))) (λf.(S (K f) I))
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