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64 lines
2.1 KiB
Python
64 lines
2.1 KiB
Python
from pytest import approx
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from wordfreq import word_frequency
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from wordfreq.numbers import digit_freq, smash_numbers
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def test_number_smashing():
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assert smash_numbers("1") == "1"
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assert smash_numbers("3.14") == "0.00"
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assert smash_numbers("24601") == "00000"
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def test_decimals():
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assert word_frequency("3.14", "el") > word_frequency("4.14", "el")
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assert word_frequency("3.14", "el") == word_frequency("3.15", "el")
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assert word_frequency("3,14", "de") > word_frequency("4,14", "de")
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assert word_frequency("3,14", "de") == word_frequency("3,15", "de")
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def test_eastern_arabic():
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assert word_frequency("٥٤", "ar") == word_frequency("٥٣", "ar")
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assert word_frequency("٤٣", "ar") > word_frequency("٥٤", "ar")
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def test_year_distribution():
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assert word_frequency("2010", "en") > word_frequency("1010", "en")
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assert word_frequency("2010", "en") > word_frequency("3010", "en")
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def test_boundaries():
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assert word_frequency("9", "en") > word_frequency("10", "en")
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assert word_frequency("99", "en") > word_frequency("100", "en")
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assert word_frequency("999", "en") > word_frequency("1000", "en")
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assert word_frequency("9999", "en") > word_frequency("10000", "en")
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def test_multiple_words():
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once = word_frequency("2015b", "en")
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twice = word_frequency("2015b 2015b", "en")
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assert once == approx(2 * twice)
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def test_distribution():
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assert word_frequency("24601", "en") > word_frequency("90210", "en")
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assert word_frequency("7", "en") > word_frequency("007", "en")
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assert word_frequency("404", "en") == word_frequency("418", "en")
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def test_3digit_sum():
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"""
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Test that the probability distribution given you have a 4-digit sequence
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adds up to approximately 1.
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"""
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three_digit_sum = sum(digit_freq(f"{num:03d}") for num in range(0, 1000))
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assert three_digit_sum == approx(1.0)
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def test_4digit_sum():
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"""
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Test that the probability distribution given you have a 4-digit sequence
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adds up to approximately 1.
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"""
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four_digit_sum = sum(digit_freq(f"{num:04d}") for num in range(0, 10000))
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assert 0.999 < four_digit_sum < 1.0
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