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Jake Prather b4b2eb2143 grammar
2015-01-31 21:22:30 -06:00

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Algorithms & Data Structures
Jake Prather
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Asymptotic Notations

What are they?

Asymptotic Notations are languages that allows us to analyze an algorithm's running time by identifying its behavior as the input size for the algorithm increases. This is also known as an algorithm's growth rate. Does the algorithm suddenly become incredibly slow when the input size grows? Does the algorithm mostly maintain it's quick run time as the input size increases? Asymptotic Notation gives us the ability to answer these questions.

Are there alternatives to answering these questions?

One way would be to count the number of primitive operations at different input sizes. Though this is a valid solution, the amount of work this takes for even simple algorithms does not justify its use.

Another way is to physically measure the amount of time the algorithm takes to complete given different input sizes. However, the accuracy and relativity (times obtained would only be relative to the machine they were computed on) of this method is bound to environmental variables such as computer hardware specifications, processing power, etc.

Types of Asymptotic Notation

In the first section of this doc we described how an Asymptotic Notation identifies the behavior of an algorithm as the input size changes. Let us imagine our algorithm as a function f, n as the input size, and f(n) being the running time. So for a given algorithm f, with input size n you get some resultant run time f(n). This results in a graph where the Y axis is the runtime, X axis is the input size, and plot points are the resultants of the amount of time for a given input size.

You can label a function, or algorithm, with an Asymptotic Notation in many different ways. Some examples are, you can describe your algorithm by it's best case, worse case, or equivalent case. The most common is to analyze your algorithm by it's worst case. This is because if you determine an algorithm's run time or time complexity, by it's best case, what if it's best case is only obtained given at a low, unrealistic, input size? It is equivalent to having a 5 meter sprinting race. That isn't the best measurement.

Types of functions, limits, and simplification

Logarithmic Function - log n
Linear Function - an + b
Quadratic Function - an^2 + bn + c
Polynomial Function - an^z + . . . + an^2 + a*n^1 + a*n^0, where z is some constant
Exponential Function - a^n, where a is some constant

These are some basic function growth classifications used in various notations. The list starts at the least fast growing function (logarithmic) and goes on to the fastest growing (exponential). Notice that as 'n', or the input, increases in each of those functions, the result clearly increases much quicker in quadratic, polynomial, and exponential, compared to logarithmic and linear.

One extremely important note is that for the notations about to be discussed you should do your best to use simplest terms. This means to disregard constants, and lower order terms, because as the input size (or n in our f(n) example) increases to infinity (mathematical limits), the lower order terms and constants are of little to no importance. That being said, if you have constants that are 2^9001, or some other ridiculous unimaginable amount, realize that simplifying will skew your notation accuracy.

Since we want simplest form, lets modify our table a bit...

Logarithmic - log n
Linear - n
Quadratic - n^2
Polynomial - n^z, where z is some constant
Exponential - a^n, where a is some constant

Big-Oh

Big-Oh, commonly written as O, is an Asymptotic Notation for the worst case, or ceiling of growth for a given function. Say f(n) is your algorithm runtime, and g(n) is an arbitrary time complexity you are trying to relate to your algorithm. f(n) is O(g(n)), if for any real constant c (c>0), f(n) <= c g(n) for every input size n (n>0).

Example 1 f(n) = 3log n + 100 g(n) = log n

is f(n) O(g(n))? is 3 log n + 100 O(log n)? Let's look to the definition of Big-Oh. 3log n + 100 <= c * log n Is there some constant c that satisfies this for all n? 3log n + 100 <= 150 * log n, n > 2 (undefined at n = 1) Yes! The definition of Big-Oh has been met therefore f(n) is O(g(n)).

Example 2 f(n) = 3*n^2 g(n) = n

is f(n) O(g(n))? is 3n^2 O(n)? Let's look at the definition of Big-Oh. 3n^2 <= c * n Is there some constant c that satisfies this for all n? No there isn't, f(n) is NOT O(g(n)).

Big-Omega

Big-Omega, commonly written as Ω, is an Asymptotic Notation for the best case, or a floor growth rate for a given function.

f(n) is Ω(g(n)), if for any real constant c (c>0), f(n) is >= c g(n) for every input size n (n>0).

Feel free to head over to additional resources for examples on this. Big-Oh is the primary notation used for general algorithm time complexity.

Ending Notes

It's hard to keep this kind of topic short, and you should definitely go through the books and online resources listed. They go into much greater depth with definitions and examples. More where x='Algorithms & Data Structures' is on it's way; we'll have a doc up on analyzing actual code examples soon.

Books

Online Resources